content

Database Management Systems

Lab Practicals

Tested on 10.6.18-MariaDB-0ubuntu0.22.04.1 except Question 4 which will be written with MySQL 8.0.37 in mind

Question 8 onwards, we are using Oracle Databases since we need to use PL/SQL. I know, I feel the same way😿 Question 12 was answered on Oracle’s LiveSQL Version: Live SQL 24.1.3, running Oracle Database 19c EE Extreme Perf - 19.17.0.0.0

[!IMPORTANT] Question 1 to 7 is done using MySQL 8.0 Command Line Client. [Tested and reviewed]
Question 8 to 12 is done using Run SQL Command Line. [Tested and reviewed]

Program 10 is skipped(PL/SQL cursor)

Program 1: Execute Single line Query and Group Functions.

Create a table INVENTORY with the following attributes(Item_No,Item_Name,Price).

CREATE TABLE inventory(item_no varchar(10) PRIMARY KEY, item_name varchar(20), price decimal(10,2));

• ✅ MySQL returned an empty result set (i.e. zero rows). (Query took 0.0015 seconds.)

Insert five tuples in the table INVENTORY.

(Doing only 2, same concept)

INSERT INTO inventory VALUES('L101', 'Laptop', 50000);

• ✅ 1 row inserted. (Query took 0.0003 seconds.)

INSERT INTO inventory VALUES('L102', 'Computer', 100000);

• ✅ 1 row inserted. (Query took 0.0002 seconds.)

Display all the tuples from the INVENTORY Table.

SELECT * FROM inventory;

• ✅ Showing rows 0 - 1 (2 total, Query took 0.0002 seconds.)

Perform single line query operations using group functions.

SELECT COUNT(*) number_of_items from inventory;

number_of_items
2

• ✅ Your SQL query has been executed successfully.

SELECT MAX(price) maximum_price FROM inventory;

maximum_price
100000.00

• ✅ Showing rows 0 - 0 (1 total, Query took 0.0002 seconds.)

SELECT MIN(price) minimum_price FROM inventory;

minimum_price
50000.00

• ✅ Showing rows 0 - 0 (1 total, Query took 0.0002 seconds.)

SELECT AVG(price) avg_amount FROM inventory;

avg_amount
75000.000000

• ✅ Showing rows 0 - 0 (1 total, Query took 0.0001 seconds.)

SELECT SUM(price) total_amount FROM inventory;

total_amount
150000.00

• ✅ Showing rows 0 - 0 (1 total, Query took 0.0001 seconds.)

Program 2: Execute DDL Commands.

Create table STUDENT with the following attributes(Register_no, Name, Mark_1,Mark_2,Mark_3).

CREATE TABLE student(register_no varchar(10) PRIMARY KEY, name varchar(20), mark_1 int, mark_2 int, mark_3 int);

• ✅ MySQL returned an empty result set (i.e. zero rows). (Query took 0.0003 seconds.)

DESC student;

• ✅ Your SQL query has been executed successfully.

Field	Type	Null	Key	Default	Extra
register_no	varchar(10)	NO	PRI	NULL
name	varchar(20)	YES		NULL
mark_1	int(11)	YES		NULL
mark_2	int(11)	YES		NULL
mark_3	int(11)	YES		NULL

Add new columns(Total, Average) to the table STUDENT.

ALTER TABLE student add(total int, average decimal(7,2));

• ✅ MySQL returned an empty result set (i.e. zero rows). (Query took 0.0003 seconds.)

desc student;

• ✅ Your SQL query has been executed successfully.

Field	Type	Null	Key	Default	Extra
register_no	varchar(10)	NO	PRI	NULL
name	varchar(20)	YES		NULL
mark_1	int(11)	YES		NULL
mark_2	int(11)	YES		NULL
mark_3	int(11)	YES		NULL
total	int(11)	YES		NULL
average	decimal(7,2)	YES		NULL

Rename the table STUDENT to STUDENT_T1.

RENAME TABLE student to student_t1;

• ✅ MySQL returned an empty result set (i.e. zero rows). (Query took 0.0004 seconds.)

Truncate the table STUDENT_T1.

TRUNCATE TABLE student_t1;

• ✅ MySQL returned an empty result set (i.e. zero rows). (Query took 0.0003 seconds.)

Drop the table STUDENT_T1.

DROP TABLE student_t1;

• ✅ MySQL returned an empty result set (i.e. zero rows). (Query took 0.0003 seconds.)

Program 3: Execute DML Commands.

Create table STUDENT with the following attributes(Register_No, Name, Mark_1, Mark_2, Mark_3,Total,Average).

CREATE TABLE student002(register_no varchar(10) PRIMARY KEY, name varchar(20), mark_1 int, mark_2 int, mark_3 int, total int, average decimal(7,2));

• ✅ MySQL returned an empty result set (i.e. zero rows). (Query took 0.0004 seconds.)

DESC student002;

• ✅ Your SQL query has been executed successfully.

Field	Type	Null	Key	Default	Extra
register_no	varchar(10)	NO	PRI	NULL
name	varchar(20)	YES		NULL
mark_1	int(11)	YES		NULL
mark_2	int(11)	YES		NULL
mark_3	int(11)	YES		NULL
total	int(11)	YES		NULL
average	decimal(7,2)	YES		NULL

Insert five tuples in the table STUDENT.(Make sure average and total fields are NULL).

(Doing only 2, same concept)

INSERT INTO student002 VALUES('S101', 'charles', 99, 100, 95, null, null);

(If the above code doesn’t work, try this:)

INSERT INTO student002 VALUES('S101', 'charles', 99, 100, 95);

• ✅ 1 row inserted. (Query took 0.0008 seconds.)

INSERT INTO student002 VALUES('S102', 'abdul', 100, 99, 100, null, null);

(If the above code doesn’t work, try this:)

INSERT INTO student002 VALUES('S102', 'abdul', 100, 99, 100);

• ✅ 1 row inserted. (Query took 0.0001 seconds.)

Display all the tuples from the table STUDENT.

SELECT * FROM student002;

• ✅ Showing rows 0 - 1 (2 total, Query took 0.0002 seconds.)

register_no	name	mark_1	mark_2	mark_3	total	average
S101	charles	99	100	95	NULL	NULL
S102	abdul	100	99	100	NULL	NULL

Find the Total and AVERAGE AND UPDATE TO THE TABLE student.

• Total=(Mark_1 + Mark_2 + Mark_3)
• Average=(Mark_1+Mark_2+Mark_3)/3.

UPDATE student002 SET total=(mark_1+mark_2+mark_3),average=(mark_1+mark_2+mark_3)/3;

• ✅ 2 rows affected. (Query took 0.0003 seconds.)

SELECT * FROM student002;

• ✅ Showing rows 0 - 0 (1 total, Query took 0.0002 seconds.)

register_no	name	mark_1	mark_2	mark_3	total	average
S101	charles	99	100	95	294	98.00
S102	abdul	100	99	100	299	99.67

Delete a tuple from the table STUDENT.

DELETE FROM student002 WHERE register_no='S101';

• ✅ 1 row deleted. (Query took 0.0003 seconds.)

SELECT * FROM student002;

• ✅ Showing rows 0 - 0 (1 total, Query took 0.0002 seconds.)

register_no	name	mark_1	mark_2	mark_3	total	average
S102	abdul	100	99	100	299	99.67

Program 4: Execute DCL and TCL Commands.

Connect the database using the command line window.

CONNECT souhrud_practical;

• ✅ MySQL returned an empty result set (i.e. zero rows). (Query took 0.0001 seconds.)

Create a table PURCHASE with the following attributes (Item_No, Item_Name,Price).

CREATE TABLE purchase(item_no varchar(4), item_name varchar(20), price decimal(10,2));

• ✅ MySQL returned an empty result set (i.e. zero rows). (Query took 0.0085 seconds.)

Insert two tuples in the PURCHASE.

INSERT INTO purchase VALUES("L101", "laptop", 50000);

• ✅ 1 row inserted. (Query took 0.0011 seconds.)

INSERT INTO purchase VALUES("L102", "desktop", 100000);

• ✅ 1 row inserted. (Query took 0.0011 seconds.)

Create a user with (User name: customer,Password:sales).

CREATE USER 'customer'@'localhost' IDENTIFIED BY 'sales';

(If the above code doesn’t work, try this:)

CREATE USER 'customer' IDENTIFIED BY 'sales';

• ✅ Query OK, 0 rows affected (0.16 sec)

Perform DCL command operations using the table PURCHASE.

GRANT ALL ON souhrud_practical.* TO 'customer'@'localhost';

• ✅ Query OK, 0 rows affected (0.12 sec)

Program 5: Implement the Nested Queries.

Create a table TEACHER with the following attributes(Tid,Tanme,Deptid).

CREATE TABLE teacher(tid int(4) PRIMARY KEY, tname varchar(20), deptid varchar(3));

• ✅ Query OK, 0 rows affected, 1 warning (0.03 sec)

Insert two tuples in the table TEACHER.

INSERT INTO teacher VALUES(1001, 'charles', 'D11');

• ✅ Query OK, 1 row affected (0.01 sec)

INSERT INTO teacher VALUES(1002, 'abdul', 'D12');

• ✅ Query OK, 1 row affected (0.01 sec)

Now, output it

select * from teacher;

• ✅ 2 rows in set (0.00 sec)

tid	tname	deptid
1001	charles	D11
1002	abdul	D12

Create a table DEPARTMENT with the following attributes(Deptid,Dname).

CREATE TABLE department(deptid varchar(10), dname varchar(20));

• ✅ Query OK, 0 rows affected (0.28 sec)

Check the attributes

DESC department;

• ✅ 2 rows in set (0.17 sec)

Insert three tuples into the DEPARTMENT Table.

INSERT INTO department VALUES('D11','computer science'),('D15','physics'),('D13', 'maths');

• ✅ Query OK, 3 rows affected (0.06 sec) Records: 3 Duplicates: 0 Warnings: 0

Now, check the output:

SELECT * FROM department;

• ✅ 3 rows in set (0.00 sec)

deptid	dname
D11	computer science
D15	physics
D13	maths

Perform nested queries using the table TEACHER and DEPARTMENT.

SELECT * FROM teacher WHERE deptid IN(SELECT deptid FROM department WHERE teacher.deptid=department.deptid);

• ✅ 1 row in set (0.04 sec)

tid	tname	deptid
1001	charles	D11

Program 6: Implement Join Operations in SQL.

Create a table EMPLOYEE with the following attributes(Emp_id, Emp_name,Edept_id).

CREATE TABLE employee(emp_id int PRIMARY KEY, emp_name varchar(20), edept_id int);

• ✅ Query OK, 0 rows affected (0.14 sec)

Insert three tuples in the table EMPLOYEE.

INSERT INTO employee VALUES(1001, 'charles', 10), (1002, 'abdul', 30), (1003, 'rohan', 30);

• ✅ Query OK, 3 rows affected (0.05 sec) Records: 3 Duplicates: 0 Warnings: 0

Create a table DEPARTMENT with the following attributes(Dept_id,Dept_name).

CREATE TABLE department(dept_id int PRIMARY KEY, dept_name varchar(20));

• ✅ Query OK, 0 rows affected (0.17 sec)

Enter Four tuples in the table DEPARTMENT.

INSERT INTO department VALUES(10, 'accounts'), (20, 'design'), (40, 'testing'), (50, 'purchase');

• ✅ Query OK, 4 rows affected (0.04 sec) Records: 4 Duplicates: 0 Warnings: 0

Perform join Operations using the table EMPLOYEE and DEPARTMENT.

Inner Join:

SELECT emp_id, emp_name, edept_id, dept_name FROM employee INNER JOIN department ON employee.edept_id=department.dept_id;

• ✅ 1 row in set (0.00 sec)

emp_id	emp_name	edept_id	dept_name
1001	charles	10	accounts

Left Outer Join:

SELECT emp_id, emp_name, edept_id, dept_name FROM employee LEFT JOIN department ON employee.edept_id=department.dept_id;

• ✅ 3 rows in set (0.00 sec)

emp_id	emp_name	edept_id	dept_name
1001	charles	10	accounts
1002	abdul	30	NULL
1003	rohan	30	NULL

Right Outer Join:

SELECT emp_id, emp_name, edept_id, dept_name FROM employee RIGHT JOIN department ON employee.edept_id=department.dept_id;

• ✅ 4 rows in set (0.00 sec)

emp_id	emp_name	edept_id	dept_name
1001	charles	10	accounts
NULL	NULL	NULL	design
NULL	NULL	NULL	testing
NULL	NULL	NULL	purchase

Full Join:

SELECT emp_id, emp_name, edept_id, dept_name FROM employee LEFT JOIN department ON employee.edept_id=department.dept_id UNION SELECT emp_id, emp_name, edept_id, dept_name FROM employee RIGHT JOIN department ON employee.edept_id=department.dept_id;

• ✅ 6 rows in set (0.02 sec)

emp_id	emp_name	edept_id	dept_name
1001	charles	10	accounts
1002	abdul	30	NULL
1003	rohan	30	NULL
NULL	NULL	NULL	design
NULL	NULL	NULL	testing
NULL	NULL	NULL	purchase

Program 7: Create a view for a particular table.

Create a table TRAIN (Train_no,Train_Nmae,Source,Destination).

CREATE TABLE train(train_no int PRIMARY KEY, train_name varchar(20), source varchar(20), destination varchar(20)); 

• ✅ Query OK, 0 rows affected (0.16 sec)

Insert three tuples in the table TRAIN.

INSERT INTO train VALUES (50001, 'malgudi exp', 'bengaluru', 'mysuru'), (50002,'karnataka exp','bengaluru','new delhi'), (50003,'shatabdi exp','bengaluru','chennai'); 

• ✅ Query OK, 3 rows affected (0.05 sec) Records: 3 Duplicates: 0 Warnings: 0

Display all the tuples from the table TRAIN.

SELECT * FROM train; 

• ✅ 3 rows in set (0.00 sec)

train_no	train_name	source	destination
50001	malgudi exp	bengaluru	mysuru
50002	karnataka exp	bengaluru	new delhi
50003	shatabdi exp	bengaluru	chennai

Perform view operations using the table TRAIN.

CREATE VIEW display_view AS SELECT * FROM train; 

• ✅ Query OK, 0 rows affected (0.06 sec)

Display Train View

 SELECT * FROM display_view;

• ✅ 3 rows in set (0.00 sec)

train_no	train_name	source	destination
50001	malgudi exp	bengaluru	mysuru
50002	karnataka exp	bengaluru	new delhi
50003	shatabdi exp	bengaluru	chennai

INSERT INTO display_view VALUES(50004,'kochuveli exp', NULL, NULL); 

• ✅ Query OK, 1 row affected (0.05 sec)

Display Train View after Operation

SELECT * FROM display_view; 

• ✅ 4 rows in set (0.00 sec)

train_no	train_name	source	destination
50001	malgudi exp	bengaluru	mysuru
50002	karnataka exp	bengaluru	new delhi
50003	shatabdi exp	bengaluru	chennai
50004	kochuveli exp	NULL	NULL

Add data to 50004 train

UPDATE train set source='bengaluru', destination='kochuveli' WHERE train_no=50004; 

• ✅ Query OK, 1 row affected (0.08 sec) Rows matched: 1 Changed: 1 Warnings: 0

Output the result

SELECT * FROM display_view;

• ✅ 4 rows in set (0.00 sec)

train_no	train_name	source	destination
50001	malgudi exp	bengaluru	mysuru
50002	karnataka exp	bengaluru	new delhi
50003	shatabdi exp	bengaluru	chennai
50004	kochuveli exp	bengaluru	kochuveli

Program 8: Implement Locks for a particular table.

Connect the database using the command line window.

CONNECT system;

• ✅ Connected.

Create table CAR with the following attributes(Model_No, Brand,Price).

CREATE TABLE car(Model_No VARCHAR(5) PRIMARY KEY, Brand VARCHAR(20), Price DECIMAL(10,2));

• ✅ Table created.

Insert five tuples in the table CAR.

INSERT INTO car VALUES('H1001','Hyundai', 1000000);
INSERT INTO car VALUES('H1002','Maruti', 800000);
INSERT INTO car VALUES('H1003','Tata', 700000);
INSERT INTO car VALUES('H1004','Honda', 600000);
INSERT INTO car VALUES('H1005','Mahindra', 500000);

• ✅ 5 row created.

Create a user with (User name: Owner, Password:car) and grant the select, update permission.

CREATE USER owner IDENTIFIED BY car;

• ✅ User created.

GRANT CONNECT TO owner;

• ✅ Grant succeeded.

GRANT SELECT ON car TO owner;

• ✅ Grant succeeded.

GRANT UPDATE ON car TO owner;

• ✅ Grant succeeded.

UPDATE car SET Price=1000000 WHERE Model_No='H1001';

• ✅ 1 row updated.

commit;

• ✅ Commit complete.

Implement the Locks using the table CAR.

LOCK TABLE car IN EXCLUSIVE MODE;

• ✅ Table(s) Locked.

Program 9: Write PL/SQL Procedure for an application using exception handling.

Create a table BANK with the following attributes(Acno, Name,Balance).

CREATE TABLE bank(acno int primary key, name varchar(20), balance decimal(10,2));

Insert two tuples in the table BANK.

INSERT INTO bank VALUES(0001, 'Souhrud', 20);
INSERT INTO bank VALUES(0002, 'Joel', 30);

Display all the tables from the table BANK.

SELECT * FROM bank;

ACNO	NAME	BALANCE
1	Souhrud	20
2	Joel	30

Perform exception handling using the table BANK.

SET SERVEROUTPUT ON;

DECLARE
  cacno bank.acno%TYPE;
  cname bank.name%TYPE;
  cbalance bank.balance%TYPE;	
BEGIN
  SELECT acno, name, balance INTO cacno, cname, cbalance 
  FROM bank 
  WHERE acno = 0001;
  
  DBMS_OUTPUT.PUT_LINE(REPLACE(cacno || '    ' || cname || '   ' || cbalance, CHR(10), ''));
EXCEPTION
  WHEN NO_DATA_FOUND THEN
    DBMS_OUTPUT.PUT_LINE('no such customer');
  WHEN OTHERS THEN
    DBMS_OUTPUT.PUT_LINE('Error');
END;
/

Output:

1   Souhrud  20

• ✅ PL/SQL procedure successfully completed.

Program 10: Write PL/SQL procedure for an application using a cursor.(skip)

Create a table BANK with the following attributes(Acno, Name,Balance).

CREATE TABLE bank(acno int primary key, name varchar(20), balance decimal(10,2));

Insert two tuples in the table BANK.

INSERT INTO bank VALUES(0001, 'Souhrud', 20);
INSERT INTO bank VALUES(0002, 'Joel', 30);

Display all the tuples from the table BANK.

SELECT * FROM bank;

ACNO	NAME	BALANCE
1	Souhrud	20
2	Joel	30

Display all the tuples from the table BANK using cursor.

SET SERVEROUTPUT ON;

DECLARE
cacno bank.acno%type;
cname bank.name%type;
cbalance bank.balance%type;
CURSOR cbank is
SELECT acno,name,balance FROM bank;
BEGIN
dbms_output.put_line('Account no.   '||'Name    '||'Balance');
dbms_output.put_line('==================================');
OPEN cbank;
LOOP
FETCH cbank into cacno,cname,cbalance;
EXIT WHEN cbank%notfound;
dbms_output.put_line(cacno||'  '||cname||'    '||cbalance);
END LOOP;
CLOSE cbank;
END;
/

Output:

Account no.   Name    Balance
==================================
1           Souhrud    20
2           Joel       30

• ✅ PL/SQL procedure successfully completed.

Program 11: Write a PL/SQL procedure for an application using functions.

Create a table LAPTOP with the following attributes(Model_No,Company_Name, Price).

CREATE TABLE laptop(model_no varchar(5), company_name varchar(20), price decimal(10,2));

Insert two tuples in the table LAPTOP.

INSERT INTO laptop VALUES('L1001', 'dell', 50000); 
INSERT INTO laptop VALUES('L1002', 'hp', 40000);

Display all the tuples in the table LAPTOP.

SELECT * FROM laptop;

MODEL	COMPANY_NAME	PRICE
L1001	dell	50000
L1002	hp	40000

Find the maximum price in the table LAPTOP using the function.

SET SERVEROUTPUT ON;

create or replace function maximum
return decimal IS
maxprice number(10,2):=0;
begin
select max(price)into maxprice from laptop;
return maxprice;
end;
/

• ✅ Function created.

declare 
n number(10,2);
begin
n:=maximum();
dbms_output.put_line('maximum price='||n);
end;
/

Output:

maximum price=50000

• ✅ PL/SQL procedure successfully completed.

Program 12: Write a PL/SQL procedure for an application using a package.

Create a table LIBRARY with the following attributes(Book_id, Book_name, B_price).

CREATE TABLE library(Book_Id INT PRIMARY KEY, Book_Name VARCHAR(40), B_Price DECIMAL(20,2));

• ✅ Table created.

Insert three tuples in the table LIBRARY.

INSERT INTO library VALUES (1001,'C# and Dotnet',200);
INSERT INTO library VALUES (1002,'Computer Communication and Networks',250);
INSERT INTO library VALUES (1003,'Database Management System',250);

• ✅ 3 row(s) inserted.

Display all the tuples from the table LIBRARY.

SELECT * FROM library;

BOOK_ID	BOOK_NAME	B_PRICE
1001	C# and Dotnet	200
1002	Computer Communication and Networks	250
1003	Database Management System	250

Create a package using the table LIBRARY.

CREATE OR REPLACE PACKAGE library_package IS
PROCEDURE ADD_NEW (B_Id VARCHAR,B_Name VARCHAR2,B_Price NUMBER);
FUNCTION DISPLAY RETURN VARCHAR2;
END library_package;
/

• ✅ Package created.

CREATE OR REPLACE PACKAGE BODY library_package IS
PROCEDURE ADD_NEW (B_Id VARCHAR,B_Name VARCHAR2,B_Price NUMBER) IS
BEGIN
INSERT INTO library VALUES(B_Id,B_Name,B_Price);
END;
FUNCTION display RETURN VARCHAR2 IS
BEGIN
RETURN 'Recorded Inserted';
END display;
END library_package;
/

• ✅ Package body created.

BEGIN
library_package.ADD_NEW('1004','OPP With JAVA',500);
dbms_output.PUT_LINE(library_package.display);
END;
/

• ✅ Recorded Inserted
  PL/SQL procedure successfully completed.

Now, Output it:

SELECT * FROM library;

BOOK_ID	BOOK_NAME	B_PRICE
1001	C# and Dotnet	200
1002	Computer Communication and Networks	250
1003	Database Management System	250
1004	OPP With JAVA	500

Source:

• General Questions were found in Syllabus
• Specific Questions are from a documents shared in the whatsapp group.